The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is ______ Hz. [ take $\pi = \frac{22}{7}$ ]

Question

Accepted Answer

D. 1. In SHM, the kinetic energy oscillates at twice the angular frequency of the displacement, so the given value must first be divided by 2 to get the oscillator's actual angular frequency.
Given $2\omega = 176$ rad/s,
$$
\omega = \frac{176}{2} = 88\ 	ext{rad/s}
$$

2. Convert angular frequency to ordinary frequency using $\omega = 2\pi f$.
Therefore,
$$
f = \frac{\omega}{2\pi} = \frac{88}{2	imes\frac{22}{7}} = \frac{88}{\frac{44}{7}}
$$
Hence,
$$
f = 88	imes\frac{7}{44} = 14\ 	ext{Hz}
$$

Hence, the frequency of the oscillator is 14 Hz, so the answer is option D.

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is ______ Hz. [ take π=227\pi = \frac{22}{7}π=722​ ]

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is ______ Hz. [ take $\pi = \frac{22}{7}$ ]